
Chapter 5 Codes
MS-880 Industrial Long Range Scanner User’s Manual 5-15
5–Codes
Code Length #1 (Interleaved 2 of 5)
Code Length #2 (Interleaved 2 of 5)
Definition: Allows user to define the symbol length. Because I 2/5 is a continuous
code, it is prone to substitution errors. Hence, a code length must be
defined and a bar code symbol must contain an even number of digits.
Note: If a start, stop or check digits are used, they are not included in
the code length count.
Usage: With I 2/5, two code lengths can be defined. When using only one sym-
bol length in an application, setting Code Length #2 to 0 (zero) to
ensure data integrity is recommended.
Serial Cmd: <K472, status,check digit status,check digit output status,code length
#1,code length #2,guard bar>
Default: 10
Options: 2 to 128, even.
Since I 2/5 characters are paired, code length must be set to an even
number. If Check Digit is enabled, add 2 to your code length. For
example, if your symbol is 10 characters plus a check digit, then enable
Code Length for 12.
Note: Typically, when printing an I 2/5 label with an odd number of dig-
its, a 0 will be added as the first character.
Note: If both Code Length #1 and Code Length #2 are set to 0, then I–
2 of 5 will be variable.
Definition: Allows user to define a second code length for I–2 of 5.
Usage: If using a second symbol, a zero or any even code length from 2 to 64
may be specified. If not using a second symbol, set Code Length #2 to
0 to ensure data integrity.
Serial Cmd: <K472, status,check digit status,check digit output status,code length
#1,code length #2,guard bar>
Default: 6
Options: 2 to 128, even.
Since I 2/5 characters are paired, code length must be set to an even
number. If Check Digit is enabled, add 2 to your code length. For
example, if your symbol is 10 characters plus a check digit, then enable
Code Length for 12.
Note: Typically, when printing an I 2/5 label with an odd number of dig-
its, a 0 will be added as the first character.
Note: If both Code Length #1 and Code Length #2 are set to 0,
then I–2 of 5 will be variable.
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